What is the moment of inertia of circular plate?
For a uniform circular disc the moment of inertia about it diameter is 100 gcm2.
What is the moment of inertia of a thin rectangular plate?
The moment of inertia of a thin uniform rectangular plate relative to the axis passing perpendicular to the plane of the plate through one of its vertices, if the sides of the plate are equal to a and b, and mass m is I=xm(a2+b2).
What is the moment of inertia for a thin ring about its diameter?
45MR2.
What is the moment of inertia of a thin circular disc of mass M and radius R about any diameter?
The moment of inertia of a uniform circular disc of mass M and radius R about any of its diameters is `1/4 MR^(2)`.
What is mass moment of inertia of circular plate Mcq?
Explanation: The mass moment of inertia of circular plate is Mr2/4.
What is the moment of inertia of a hollow cylinder?
Solution : The moment of inertia of the cylinder about its axis = `MR^2`. Using parallel axes theorem, `I=I_0+MR^2=MR^2+MR^2=2MR^2. `Similarly, the moment of inertia of a hollow sphere about a tangent is `2/3MR^2+MR^2=5/3MR^2`.
What will be the moment of inertia of a circle in cm4 of diameter is 10cm?
What will be the moment of inertia of a circle in cm4 of diameter is 10cm? = 491.07 cm4.
What is the moment of inertia about the centre for a thin circular ring of radius R?
EXPLANATION:
| Body | Axis of Rotation | Moment of inertia |
|---|---|---|
| Uniform circular ring of radius R | diameter | M R 2 2 |
| Uniform circular disc of radius R | perpendicular to its plane and through the center | M R 2 2 |
| Uniform circular disc of radius R | diameter | M R 2 4 |
| A solid sphere of radius R | diameter | 2 5 M R 2 |
How do you find the moment of inertia of a ring diameter?
${{I}_{x}}\And {{I}_{y}}$are moments of inertia of a ring about diameter along x and y axes respectively. Therefore moment of inertia about the diameter of a uniform ring is \[{{I}_{d}}=\dfrac{M{{R}^{2}}}{2}\]. In the question, it is given that moment of inertia about the centre of the ring is \[I\].
What is the moment of inertia of a uniform circular disc of mass M and radius R rotating about an axis passing through its centre and perpendicular to its plane?
So, I=21MR2+MR2=23MR2.