## What is the moment of inertia of circular plate?

For a uniform circular disc the moment of inertia about it diameter is 100 gcm2.

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### What is the moment of inertia of a thin rectangular plate?

The moment of inertia of a thin uniform rectangular plate relative to the axis passing perpendicular to the plane of the plate through one of its vertices, if the sides of the plate are equal to a and b, and mass m is I=xm(a2+b2).

#### What is the moment of inertia for a thin ring about its diameter?

45MR2.

**What is the moment of inertia of a thin circular disc of mass M and radius R about any diameter?**

The moment of inertia of a uniform circular disc of mass M and radius R about any of its diameters is `1/4 MR^(2)`.

**What is mass moment of inertia of circular plate Mcq?**

Explanation: The mass moment of inertia of circular plate is Mr2/4.

## What is the moment of inertia of a hollow cylinder?

Solution : The moment of inertia of the cylinder about its axis = `MR^2`. Using parallel axes theorem, `I=I_0+MR^2=MR^2+MR^2=2MR^2. `Similarly, the moment of inertia of a hollow sphere about a tangent is `2/3MR^2+MR^2=5/3MR^2`.

### What will be the moment of inertia of a circle in cm4 of diameter is 10cm?

What will be the moment of inertia of a circle in cm4 of diameter is 10cm? = 491.07 cm4.

#### What is the moment of inertia about the centre for a thin circular ring of radius R?

EXPLANATION:

Body | Axis of Rotation | Moment of inertia |
---|---|---|

Uniform circular ring of radius R | diameter | M R 2 2 |

Uniform circular disc of radius R | perpendicular to its plane and through the center | M R 2 2 |

Uniform circular disc of radius R | diameter | M R 2 4 |

A solid sphere of radius R | diameter | 2 5 M R 2 |

**How do you find the moment of inertia of a ring diameter?**

${{I}_{x}}\And {{I}_{y}}$are moments of inertia of a ring about diameter along x and y axes respectively. Therefore moment of inertia about the diameter of a uniform ring is \[{{I}_{d}}=\dfrac{M{{R}^{2}}}{2}\]. In the question, it is given that moment of inertia about the centre of the ring is \[I\].

**What is the moment of inertia of a uniform circular disc of mass M and radius R rotating about an axis passing through its centre and perpendicular to its plane?**

So, I=21MR2+MR2=23MR2.