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How can I get previous date in Linux?

How can I get previous date in Linux?

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  1. Yesterday date YES_DAT=$(date –date=’ 1 days ago’ ‘+%Y%d%m’)
  2. Day before yesterdays date DAY_YES_DAT=$(date –date=’ 2 days ago’ ‘+%Y%d%m’)

How do I get the 7 day back date in Unix?

As a rule, Unix does not allow the date command to be used in this way….6 Answers

  1. pday=7 CURRENT= date +”%F %T” –date “$pday days ago” echo $CURRENT how abt this. – jcrshankar.
  2. That’s fine.
  3. Likewise, GNU date is unlikely to be installed on a Unix system (likely only Linux and constructs such as Cygwin).

How do I subtract a day from a date in Linux?

  1. I had to modify this to $ date “–date=${dataset_date} -${date_diff} 1 day” +%Y%m%d to actually subtract the date… otherwise it would have added one day.
  2. @x_mtd Yes, you need to set the variable date_diff .
  3. Very slight improvement to the command – date –date=”${dataset_date} -${date_diff} day” +%Y-%m-%d.

How do I find the previous date in Unix?

NOTE: Command, `TZ=CST+24 date +%y%m%d` for yesterday’s date I found at some thread, on the same board. If you have GNU date avaialbe it has more powerful features.

How do you subtract dates in Unix?

The easiest way is to convert the date to a unix time_t value (i.e. seconds since the beginning of the epoch, or ‘1-1-1970 00:00:00’), and then substract 30 days * 86400 seconds per day from that number. e.g. the following example uses set -x so that you can see the value of the D variable as it changes.

How do I find the last date of a previous month in Unix?

$ date –date=”$(date +%Y-%m-15) -1 month” +’Last month was %B! ‘ Last month was June! It doesn’t move to the next day, it takes the number of days in the prior month and subtracts it from DoY, based on what I’ve seen. date –date=”03/31/2015 -1 month” +’Date: %m-%d-%Y’ returns “Date: 03-03-2015”.

How do you subtract a day in Unix?

How do I echo date in bash script?

Sample shell script to display the current date and time #!/bin/bash now=”$(date)” printf “Current date and time %s\n” “$now” now=”$(date +’%d/%m/%Y’)” printf “Current date in dd/mm/yyyy format %s\n” “$now” echo “Starting backup at $now, please wait…” # command to backup scripts goes here # …

How do I subtract one day from a date in Unix?

How do I find the difference between two dates in Linux?

Try this: DATEfirstnum=$(date -d “$1” +%s) DATElastnum=$(date -d “$2” +%s) Also, this script will not be able to calculate the difference between two different years. +%j refers to day of year (001.. 366) so ./ 12/31/2001 12/30/2014 outputs -1.

How do you find the difference between two dates in Unix?

  1. datediff() {
  2. d1=$(date -d “$1” +%s)
  3. d2=$(date -d “$2” +%s)
  4. echo $(( (d1 – d2) / 86400 )) days.
  5. }
  6. $ datediff ‘1 Nov’ ‘1 Aug’
  7. 91 days.

How do I get previous month in Linux?

date –date=”03/31/2015 -1 month” +’Date: %m-%d-%Y’ returns “Date: 03-03-2015”.